Am trying to determine the silver content from electrolyte solution of silver cell by titration between electrolyte solution and potassium thiosulphate - Assaying, Microscopy, Mineralogy & XRF/XRD - Metallurgist & Mineral Processing Engineer

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Am trying to determine the silver content from electrolyte solution of silver cell by titration betw ... (6 replies)

2 years ago

koki 2 years ago

my question is how do i convert back the final concentration i obtained from titration to represent the whole lot, cause am only taking 100mL from roughly 150L. My final concentration from titration i calculate in "g/L

Jorge

2 years ago

Jorge 2 years ago

1 like by David

It is important to indicate that results are accurate only if the sample is representative of the solution under analysis. In this way, solution should be agitated mechanically before taking a sample. If for any reason, there is sludge in the cell, the solution should be agitated mechanically and allowed to stand for at least 12 hours, ideally 24 hours is better, to take a sample. It is a good practice to get samples from different locations and combine them to get a representative sample.

The titrant could be 0.1N KSN and FAS the indicator. The reagents added to the solution are sulphuric acid and nitric acid. The silver content using 5 ml of solution can be determined using the formula below,

Ag (oz/gal) = ml x 2.877 x N

Where, ml = milliliters used to perform the titration

N = Normality

Also, AgCN (oz/gal) = Ag x 1.241

koki

2 years ago

koki 2 years ago

what is this factor of 2.877 and 1.241

Jorge

2 years ago

Jorge 2 years ago

They are correction factors