Grinding & Classification Circuits

Grinding & Classification Circuits

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Ash Product Size in Rotary Breaker (4 replies)

(unknown)
8 years ago
(unknown) 8 years ago

What is the optimum/possible ash product size P80 that be obtained a comminution operation using rotary breaker in coal preparation ? What modifications can I make to improve ash reduction?

Helena Russell
8 years ago
Helena Russell 8 years ago
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The size of the holes in the breaker shell determines the size of rocks that get rejected. If a breaker has 50 mm diameter holes, then the proportion of ash that is rejected is going to be the proportion of +50 mm rocks contained in the breaker feed.

The breaker will not reject ash finer than 50 mm in this example. You need to use either heavy media separation or flotation to remove that fine ash from the coal.

(unknown)
8 years ago
(unknown) 8 years ago
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Thanks for your response. I have a fix size of holes in the breaker shell. I wanted to improve the amount of rocks rejected through the breaker without changing the size of holes. Can u suggest any alternative ?

Helena Russell
8 years ago
Helena Russell 8 years ago
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If the hole size is fixed and the mine delivers a coal of a certain ash content, then you must change something if you want to achieve a different ash content.

No changing the holes == no changing the ash content.

Victor Bergman
8 years ago
Victor Bergman 8 years ago
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I would suggest you aim to increase the 'open area' of the breaker. This is the proportion or quantity of holes relative to the total surface area. This may impose structural constraints, but ultimately a higher open area will allow you to maximize rejection. You may have to consider stiffer plates if you opt for the higher open area panels.

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