Grinding & Classification Circuits

Grinding & Classification Circuits2018-06-17T09:51:34-04:00
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What is the difference between pearlitic liners and white cast iron liners in SAG mills? (4 replies and 4 comments)

MSKabir
1 month ago
MSKabir 1 month ago

After perusing through research articles I found out that the two most commonly used mill liners are pearlitic steel and white cast irons. However, I was wondering, what situations would involve using pearlitic steel as liner material or vice versa during SAG milling. Does it depend on the mill charge, ore type, etc. Are there any studies regarding choice of mill liners? I would really appreciate assistance from experts. Thank you.

David
1 month ago
David 1 month ago

Pearlitic steel - The stuff you read must be Rated "R" because I never hear of it.

Chrome Moly Steel are for SAG mills at 301-402 Brinell

White Iron is for AG mills at much higher Brinell

MSKabir
1 month ago

Thank you David for the valuable feedback. I would be really grateful if you could elaborate on this matter since I am new in this field. Why White iron is used in AG mills and not in SAG mills? Is it due to the ore type ?

David
1 month ago
David 1 month ago

White iron cannot take grinding ball impact.

MSKabir
1 month ago

Thank you so much for the feedback. Really appreciate your patience and support.

MSKabir
1 month ago

Dear David, If you don't mind my asking. Is there a maximum value of impact in terms of Joules that occurs inside a SAG mill, i.e. a colleague of mine reported that the maximum impact inside a SAG mill can go upto 450 J. I was thinking as to the validity of this report. Could you kindly share your opinion on this

David
1 month ago
David 1 month ago

i have no idea

SmartDog
1 month ago
SmartDog 1 month ago
1 like by David

The maximum value would be determined by the maximum size (mass) of the largest particle/media and the velocity of the particle/media if it is flung (high rotational speed).  A theoretical maximum could be calculated since joules are equal to:  J =(kg * m^2)/(sec^2)

The actual maximum will probably be less than this due to resistance of other particle/media.

MSKabir
1 month ago

Thank you so much for the feedback

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